4x^2+8x+4-6x=2+6x+2x^2

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Solution for 4x^2+8x+4-6x=2+6x+2x^2 equation: 



4x^2+8x+4-6x=2+6x+2x^2

We move all terms to the left:

4x^2+8x+4-6x-(2+6x+2x^2)=0

We add all the numbers together, and all the variables

4x^2-(2+6x+2x^2)+2x+4=0

We get rid of parentheses

4x^2-2x^2-6x+2x-2+4=0

We add all the numbers together, and all the variables

2x^2-4x+2=0

a = 2; b = -4; c = +2;
Δ = b2-4ac
Δ = -42-4·2·2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{4}{4}=1$

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